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mysql 获取 间隔

select timestampdiff(minute,"2016-08-09 11:15:16","2016-08-09 11:55:16");

语句是有的, 不过运算量较大, 如下, 测试通过 SELECT * from (Select id,(@rowNum:=@rowNum+1) as rowNo From t_user, (Select (@rowNum :=0) ) b order by id asc) as a where mod(a.rowNo, 3) = 1Select id,(@rowNum:=@rowNum+1) as rowNo Fro...

你不是有id这一项吗,那你可直接指定id的范围啊,也就是 SELECT * FROM t WHERE (id > 10 and id 61 and id

你表中的数据,根据你的题目,应该是全部显示才对。是小于5秒还是5分钟? 下面这个是 两条数据间小于5秒的记录的查询语句 select *,timestampdiff(second,t1.time,(select time from table3 where t1.idid order by id desc limit 1),t1.time ) ...

SELECT SUBSTRING_INDEX(name, '=', 1) AS city, SUBSTRING_INDEX(name, '=', -1) AS name FROM TB_USER; 上面那个是用于查询的,如果是想修改数据库,则用下面的语句: ALTER TABLE TB_USER ADD COLUMN city VARCHAR(16) NULL; UPDATE TB_USER ...

select count(*) from sometable where datetimecolumn>=UNIX_TIMESTAMP('2010-03-01 00:00:00') and datetimecolumn

--一个语句还真想不出怎么做, --建一个临时表,把下面查出的数据保存在里面,按rank分组,having count(*)>1 ,找出记录数大于1的rank就是你要的记录 select name,dtime,rank,ptime,ptime2 from(select cg_tmp.*, @rownum :=@rownum + 1,if(TIME...

select * from t_rainfall where time>='开始时间' and time

用时间戳来计算 SELECT (UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP('2015-04-20 15:12:12'))/60;也就是得到两个时间相差的秒数,然后除60得到分种。

select * from table where 时间字段 between '2010-7-12 11:18:54' and '2010-7-12 11:22:20'

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