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mysql 时间间隔查询

一楼的写错,二楼的乱写, 假设存在一主键列id select * from 表 where id in(select id from 表 group by id haing count(数据列)=3) 这句就行了~

select count(*) from sometable where datetimecolumn>=UNIX_TIMESTAMP('2010-03-01 00:00:00') and datetimecolumn

select * from table where 时间字段 between '2010-7-12 11:18:54' and '2010-7-12 11:22:20'

你表中的数据,根据你的题目,应该是全部显示才对。是小于5秒还是5分钟? 下面这个是 两条数据间小于5秒的记录的查询语句 select *,timestampdiff(second,t1.time,(select time from table3 where t1.idid order by id desc limit 1),t1.time ) ...

TIMESTAMPDIFF(interval,datetime_expr1,datetime_expr2) www.2cto.com 说明: 返回日期或日期时间表达式datetime_expr1 和datetime_expr2the 之间的整数差。其结果的 单位由interval 参数给出。interval 的法定值同TIMESTAMPADD()函数说明中所列...

1. sql 中字段不要加‘ ’ =>select *, caozuo as caozuo from mj_searched (多此一举吗? 有*了 还艺单独查caozuo) 2. select *, caozuo as caozuo from mj_searched where publishedtime >= '2013-02-12' AND publishedtime

select dtime,name from(select name,dtime,rank,ptime,ptime2 from(select cg_tmp.*, @rownum :=@rownum + 1,if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)

mysql常用的日期加减函数与实例教程 MySQL 日期类型 MySQL 日期类型:日期格式、所占存储空间、日期范围 比较。 日期类型 存储空间 日期格式 日期范围 ------------ --------- --------------------- -----------------------------------------...

时间段统计,可以采用 hour(subscribe_time) 取出小时然后分层。思路: select uid ,CASE WHEN HOUR(subscribe_time) BETWEEN 0 AND 1 THEN '00:00:00' WHEN HOUR(subscribe_time) BETWEEN 2 AND 3 THEN '02:00:00' ... ELSE '23:00:00' END -- ...

不用left join 直接把连接条件放到where里: SELECT a.username,b.tatle,b.last_time FROM test AS a, test1 AS b WHERE a.id = b.user_id AND a.co='".$usermes."' AND b.tatle>1 ORDER BY last_time 或者使用子查询来减少笛卡尔积: SELECT a....

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